Consider the following four elements which ar | vedclass

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(D) Given that $Y$ is in the $16^{th}$ group and $2^{nd}$ period,$Y$ is Oxygen $(O)$.Based on the arrangement,$X$ is Sulfur $(S)$,$W$ is Phosphorus $(

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$Y$ exhibits maximum electron affinity

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(D) Given that $Y$ is in the $16^{th}$ group and $2^{nd}$ period,$Y$ is Oxygen $(O)$.Based on the arrangement,$X$ is Sulfur $(S)$,$W$ is Phosphorus $(P)$,and $Z$ is Chlorine $(Cl)$.$1$. Electronegativity increases across a period and decreases down a group. Among $O, S, P, Cl$,Oxygen $(O)$ has the highest electronegativity.$2$. Catenation property is maximum for elements that can form strong bonds with themselves. Among these,Sulfur $(S)$ shows significant catenation,but Carbon is usually the highest. However,in this specific set,$S$ $(X)$ is the correct choice for the given context.$3$. Electron affinity generally increases across a period. Chlorine $(Cl)$ has the highest electron affinity among the elements in the $3^{rd}$ period. Thus,$Z$ $(Cl)$ has the maximum electron affinity.$4$. Statement $D$ claims $Y$ $(O)$ has the maximum electron affinity,which is incorrect because $Cl$ $(Z)$ has a higher electron affinity than $O$ $(Y)$.

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